broodjeaap/go-watch
1
0
Fork 0
Code Issues Pull requests Projects Releases Packages Wiki Activity Actions

bug fix for multiple cron jobs starting for a watch

Browse source
This commit is contained in:
BroodjeAap 2022-12-19 20:20:05 +00:00
parent d23b14a643
commit 1458918106
1 changed files with 4 additions and 2 deletions
Show stats Download patch file Download diff file Expand all files Collapse all files

6
main.go
View file

@ -134,7 +134,8 @@ func (web *Web) initCronJobs() {
web.db.Model(&Filter{}).Find(&cronFilters, "type = 'cron' AND var2 = 'yes'")
web.cronWatch = make(map[uint]cron.EntryID, len(cronFilters))
web.cron = cron.New()
for _, cronFilter := range cronFilters {
for i := range cronFilters {
cronFilter := &cronFilters[i]
entryID, err := web.cron.AddFunc(cronFilter.Var1, func() { triggerSchedule(cronFilter.WatchID, web, &cronFilter.ID) })
if err != nil {
log.Println("Could not start job for Watch: ", cronFilter.WatchID)
@ -473,7 +474,8 @@ func (web *Web) importWatch(c *gin.Context) {
c.AbortWithError(http.StatusBadRequest, err)
return
}
for _, filter := range export.Filters {
for i := range export.Filters {
filter := &export.Filters[i]
if filter.Type == "cron" {
entryID, err := web.cron.AddFunc(filter.Var1, func() { triggerSchedule(filter.WatchID, web, &filter.ID) })
if err != nil {